September 2010 Archives
I recently received this question...
JC
How do I decide whether to choose a volumetric
or gravimetric feeder?
Note: A gravimetric feeder measures the flow's weight and adjusts the feeder output to maintain the desired set point. On the other hand, a volumetric feeders, by definition, do not measure the weight of the flow.
My Response
Having said
this, volumetric feeders are inexpensive and simple but are open loop devices.
They will not detect or make adjustments for changes in material density. Because
they are open loop devices, volumetric feeders are also unable to measure the
flow for data acquisition. A volumetric feeder may be good for your application
if your material has little variation in density and pellet uniformity.
Most
materials do have variations in density great enough to warrant the use of a
gravimetric feeder.
Most feeder
manufacturers have the resources to determine whether a given material can be
fed volumetrically at a required accuracy or if a gravimetric feeder is
required.
You must
also consider what you will be feeding based on cost and concentration. If you
need to feed a material in at 1% by weight a gravimetric feeder is almost
always a must. Also, for expensive additives, the material saved by having a
gravimetric feeder may pay for itself.
-Andy
Conditions For The Dynamic Check Ring Repeatability Test
I received
this inquiry the last week...
Karl
I have a single cavity mold with a
part varying in wall thickness from 3 to 5 mm. The part is warping near the
transition of the thin to thick section. What can I do to overcome this problem?
My Response
Like all
warpage yours is caused by differential shrinkage. In this case it sounds like
you have an uneven temperature gradient throughout the wall thickness of the
part.
You should
start by checking your coolant temperatures. If the cooling lines enter on the
thin side of the part and exit on the thick... the water temperature will already
be higher on the exit side of the mold. I suggest hooking up your cooling lines
on the thick side of the part first.
Also, compare the entering and exiting water temps to ensure the difference is not to great. If your exiting water temperature is fairly greater than your entrance temperature you may want to consider getting a more powerful chiller.
A chiller
with a stronger pump and higher volumetric throughput will have better cooling
uniformity and water temperature throughout the mold.
You may also
want to try increasing the packing pressure to reduce the amount of material
shrinkage, increase the pack time until the part weight no longer increases, or
profile your packing pressure to obtain a more uniform shrinkage across the
part.
-Andy
I was just asked...
JW
What factors should I take into account when calculating the capacity of a new dryer system?
My Response
When calculating the capacity of a dryer system you need to determine your total dried material consumption. Your dried material consumption can be calculated by multiplying the number of machines by their respective output in pounds. If you have 10 machines consuming 4 ounces of plastic a minute you are consuming 150 lb/hr.
Once you determine your material usage you must take into account the drying time of your material. Most plastics will vary in the type, extent, and duration of drying needed for the application. This must be determined before the dryer capacity can be calculated. Ask the dryer manufacturer typical drying times for the material you are processing. Multiply your hourly material consumption by the drying time and your result is the minimum dryer capacity. For instance, in the example above if the material drying time was 2 hours the dryer capacity would have to be at least 300 pounds.
Additional Comments
The example above was for the minimum capacity needed. If the dryer manufacturer offers a 400 pound capacity machine you may want to choose that instead, in case you decide to expand your production... or if the material takes slightly longer to dry.
-Andy
I was recently asked...
George
We just received new material and started getting burn marks on our parts near the end of fill. What do you think is causing this and how can it be fixed?
My Response
Burn marks usually appear when high temperature gas combusts in front of the melt during mold filling. In your case the new material may have a slightly higher flow rate and the mold is not venting quick enough with your current injection velocity. You should check and make sure your vents are clean and able to vent properly.
Many polymers gas-off in the molten state releasing particles that can clog the venting system. You may also want to check the melt flow rate and compare it with data from previous batches of material. If possible you may want to increase your fill time a bit to allow for longer venting.
-Andy
I was asked the question...
Dan
"How one will decide the ejector pin diameter to eject the part safely
without any stress mark observed on the part?"
My Comments
To avoid permanent distortion of the plastic moldings, the number, location, and design of the ejector components must be developed to apply a low and uniform state of stress across the moldings. If the ejector force is uniformly distributed across many points in the mold cavity, then the molding will be uniformly ejected from the mold without any permanent distortion.
My Response
You must first have an estimate of the ejection force required to remove a molding from the core. The ejection force required to remove a molding from a mold core is a function of the normal force between the surface of the molding and the surface of the mold, together with the associated draft angle, the coefficient of friction, and the vacuum force. The coefficient of friction will vary from approximately .5 for highly polished surfaces to more than 1.0 for rough or textured surfaces.
The Ejection Force will then be:
Cos(Draft Angle) x Coefficient of Friction x Force(normal) + Vacuum force
There is a minimum push area that is required to avoid excessive shear stress on the plastic molding. More ejector pins will increase the pushing area and reduce the shear stress at each ejector pin location. The mold should be designed such that the perimeter around all the ejector pins provides a shear stress about one half the yield stress of the plastic material. The following equation relates the total perimeter of the ejector pins with the ejection force, plastic yield stress, and wall thickness.
Sum(Perimeter of Ejector Pins) > [2 x Ejection Force]
Plastic Yield Stress x Wall Thickness
If you cannot add additional ejector pins you will have to increase the ejector pin diameters until the sum of their perimeters satisfies the equation above. If more pins were added the diameters could be smaller as long as the equation above was satisfied.
-Andy
I was just asked
Jim
"What is the value of having a minimum screw recovery alarm? I can see the maximum happening but the minimum I'm not so sure. I guess if someone puts the screw speed up to purge and does not put it back it may be useful. Is there anything else I might be missing?"
My Response
I believe you are correct Jim. Sometimes companies put alarms and options on the machine just because it's easy to program.
Additional Thoughts
The only benefit to such an alarm may be to monitor tampering of screw RPM but this is extremely rare.
-Andy